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15y^2+44y+21=0
a = 15; b = 44; c = +21;
Δ = b2-4ac
Δ = 442-4·15·21
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-26}{2*15}=\frac{-70}{30} =-2+1/3 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+26}{2*15}=\frac{-18}{30} =-3/5 $
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